Based on your understanding of activities determine if a react...

Question

Based on your understanding of activities determine if a reaction occurs and if so provide the products formed.

Zn (s) + NiCl₂ (aq) →

Accepted Answer

in this practice question, it says, based on your understanding of activities, determine if of reaction occurs and if so, the products form. All right here we don't have hydrogen involved. So we're not trying to displace zinc, not trying to displace hydrogen. What isn't trying to replace? Well, we have zinc here, and we have nickel. Here are two months, so if we look at our activity Siri's chart, you'll see that zinc is in the second grouping and nickel is right below it in the third grouping. Remember, if you're above higher up in the activity, Siri's, you are more reactive. Your activity increases. You can displace elements below you so against and zinc is higher up, it can displace nickel. So we're going to say here that zinc remember to transition metal, but its charge is always two plus when it has a charge and it's gonna have a charge because it's going to connect with a non metal Corrine, which has a charge of minus one. The numbers are different, so they crisscrossed. So we have zinc chloride here, a quiz based on our side ability rules plus nickel now has been displaced and kicked out when a medal is by itself, it's in its natural state, and it will be a solid if we look. We have one zinc on each side, one nickel on each side to chlorine on each side, so we don't have to balance anything. It's already balanced. So again here we're trying to displace one medal by another medal. Look at your activity. Siri's chart. If the element is on higher up, it can displace elements below it. Since zinc is higher up the nickel, it can displace nickel.

Based on your understanding of activities determine if a reaction occurs and if so provide the products formed. Zn (s) + NiCl2 (aq) →

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Based on your understanding of activities determine if a reaction occurs and if so provide the products formed.
Zn (s) + NiCl₂ (aq) →