What is the molarity of a solution containing 1.54 moles of NaOH in 2.5 \times 10^2 mL of solution?

• A. 0.154 M
• B. 0.616 M
• C. 1.54 M
• D. 6.16 M

Answer: (B)

Verified step by step guidance

1. Identify the given information: moles of solute (NaOH) = 1.54 moles, volume of solution = 2.5 \times 10^{2} mL.
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: 1 L = 1000 mL, so volume in liters = \frac{2.5 \times 10^{2}}{1000}.
3. Recall the formula for molarity (M): \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\).
4. Substitute the values into the molarity formula: \(M = \frac{1.54}{\text{volume in liters}}\).
5. Calculate the molarity by performing the division to find the concentration in moles per liter.