What is the molarity of a solution containing 1.54 mol of NaOH in 2.5 \times 10^2 mL of solution?

• A. 6.16 M
• B. 0.154 M
• C. 0.616 M
• D. 1.54 M

Answer: (C)

Verified step by step guidance

1. Identify the formula for molarity, which is defined as the number of moles of solute divided by the volume of the solution in liters: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
2. Convert the volume of the solution from milliliters to liters because molarity requires volume in liters. Use the conversion factor \$1\,\text{L} = 1000\,\text{mL}\(: \)\text{volume in liters} = \frac{2.5 \times 10^2\,\text{mL}}{1000}$.
3. Substitute the given values into the molarity formula: moles of NaOH = 1.54 mol, and volume in liters as calculated in the previous step.
4. Calculate the molarity by dividing the moles of NaOH by the volume in liters: \(M = \frac{1.54}{\text{volume in liters}}\).
5. Interpret the result to determine which of the provided answer choices matches the calculated molarity.