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Multiple Choice
What is the hybridization of the central atom in BCl_3?
A
sp
B
sp^3
C
sp^2
D
dsp^3
Verified step by step guidance
1
Identify the central atom in BCl_3, which is boron (B).
Determine the number of valence electrons around the central atom. Boron has 3 valence electrons, and each chlorine atom contributes one electron for bonding.
Draw the Lewis structure of BCl_3, showing boron bonded to three chlorine atoms with single bonds and no lone pairs on boron.
Count the regions of electron density (bonding and lone pairs) around the central atom. In BCl_3, there are three bonding regions and zero lone pairs.
Use the steric number (number of regions of electron density) to determine hybridization. A steric number of 3 corresponds to sp^2 hybridization.