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Multiple Choice
What is the molecular geometry of PF_5?
A
Octahedral
B
Square pyramidal
C
Trigonal bipyramidal
D
Tetrahedral
Verified step by step guidance
1
Identify the central atom in the molecule PF_5, which is phosphorus (P).
Determine the number of valence electrons for phosphorus (5 valence electrons) and fluorine (7 valence electrons each).
Calculate the total number of bonding pairs by noting that PF_5 has five fluorine atoms bonded to phosphorus, so there are 5 bonding pairs and no lone pairs on the central atom.
Use the VSEPR (Valence Shell Electron Pair Repulsion) theory to predict the molecular geometry. Since there are 5 bonding pairs and 0 lone pairs around phosphorus, the electron pairs arrange themselves to minimize repulsion.
Recognize that the arrangement of 5 bonding pairs around a central atom corresponds to a trigonal bipyramidal geometry, with three atoms in an equatorial plane and two atoms in axial positions.