How many moles of nitrogen atoms (N) are present in 0.245 g of dinitrogen monoxide (N_2O)?

• A. 0.00544 mol
• B. 0.00700 mol
• C. 0.00833 mol
• D. 0.0111 mol

Answer: (D)

Verified step by step guidance

1. Calculate the molar mass of dinitrogen monoxide (N\_2O) by summing the atomic masses of its atoms: 2 nitrogen atoms and 1 oxygen atom. Use the atomic masses approximately as N = 14.01 g/mol and O = 16.00 g/mol. The molar mass \( M \) is given by \( M = 2 \times 14.01 + 16.00 \).
2. Convert the given mass of dinitrogen monoxide (0.245 g) to moles using the molar mass calculated in step 1. Use the formula \( n = \frac{\text{mass}}{\text{molar mass}} \), where \( n \) is the number of moles of N\_2O.
3. Determine the number of moles of nitrogen atoms by recognizing that each mole of N\_2O contains 2 moles of nitrogen atoms. Multiply the moles of N\_2O by 2 to get the moles of nitrogen atoms: \( n_{\text{N atoms}} = 2 \times n_{\text{N}_2\text{O}} \).
4. Write down the final expression for the moles of nitrogen atoms in terms of the given mass and molar masses: \( n_{\text{N atoms}} = 2 \times \frac{0.245}{2 \times 14.01 + 16.00} \).
5. Evaluate the expression to find the number of moles of nitrogen atoms present in 0.245 g of dinitrogen monoxide.