What volume in liters of a 0.320 M Mg(NO_3)_2 solution contains 45.0 g of Mg(NO_3)_2?

• A. 1.41 L
• B. 0.225 L
• C. 0.141 L
• D. 0.439 L

Answer: (D)

Verified step by step guidance

1. Calculate the molar mass of Mg(NO\_3)\_2 by adding the atomic masses of Mg, N, and O atoms: Mg (1 × 24.31 g/mol), N (2 × 14.01 g/mol), and O (6 × 16.00 g/mol).
2. Convert the given mass of Mg(NO\_3)\_2 (45.0 g) to moles using the molar mass calculated: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\).
3. Use the molarity definition to relate moles and volume: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\).
4. Rearrange the molarity formula to solve for volume: \(\text{volume} = \frac{\text{moles of solute}}{M}\).
5. Substitute the moles of Mg(NO\_3)\_2 and the molarity (0.320 M) into the volume formula to find the volume of solution containing 45.0 g of Mg(NO\_3)\_2.