What volume (in L) of a 0.724 M NaI solution contains 0.405 mol of NaI?

• A. 0.724 L
• B. 0.293 L
• C. 0.560 L
• D. 1.79 L

Answer: (C)

Verified step by step guidance

1. Identify the known quantities: the molarity (M) of the NaI solution is 0.724 M, and the amount of NaI in moles is 0.405 mol.
2. Recall the definition of molarity, which relates moles of solute to volume of solution: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
3. Rearrange the molarity formula to solve for volume: \(V = \frac{\text{moles of solute}}{M}\).
4. Substitute the known values into the rearranged formula: \(V = \frac{0.405\ \text{mol}}{0.724\ \text{mol/L}}\).
5. Calculate the volume from the expression above to find the volume of the NaI solution that contains 0.405 mol of NaI.