How many moles of aluminum are present in 3.2 × 10^{25} atoms of aluminum?

• A. 0.53 moles
• B. 5.3 moles
• C. 1.9 moles
• D. 53.2 moles

Answer: (D)

Verified step by step guidance

1. Identify the given quantity: 3.2 \times 10^{25} atoms of aluminum.
2. Recall that 1 mole of any substance contains Avogadro's number of atoms, which is approximately 6.022 \times 10^{23} atoms/mole.
3. Set up the conversion from atoms to moles using the relationship: \(\text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}}\).
4. Substitute the given values into the formula: \(\text{moles of Al} = \frac{3.2 \times 10^{25}}{6.022 \times 10^{23}}\).
5. Perform the division to find the number of moles of aluminum (do not calculate the final value here, just set up the expression).