How many moles of nitrogen atoms (N) are present in 0.231 g of N_2O?

• A. 0.0079 mol
• B. 0.0231 mol
• C. 0.0158 mol
• D. 0.0052 mol

Answer: (C)

Verified step by step guidance

1. Identify the chemical formula of the compound: N\_2O, which contains 2 nitrogen atoms per molecule.
2. Calculate the molar mass of N\_2O by adding the atomic masses of its elements: 2 nitrogen atoms and 1 oxygen atom. Use atomic masses approximately 14.01 g/mol for nitrogen and 16.00 g/mol for oxygen.
3. Determine the number of moles of N\_2O in 0.231 g by using the formula: \(\text{moles of N}_2\text{O} = \frac{\text{mass of N}_2\text{O}}{\text{molar mass of N}_2\text{O}}\).
4. Since each mole of N\_2O contains 2 moles of nitrogen atoms, multiply the moles of N\_2O by 2 to find the moles of nitrogen atoms: \(\text{moles of N atoms} = 2 \times \text{moles of N}_2\text{O}\).
5. Express the final answer as the number of moles of nitrogen atoms present in 0.231 g of N\_2O.