How many moles of NaCl are present in 0.500 L of a 1.5 M NaCl solution?

• A. 1.5 mol
• B. 0.50 mol
• C. 0.75 mol
• D. 0.33 mol

Answer: (C)

Verified step by step guidance

1. Identify the given information: the volume of the NaCl solution is 0.500 L and the molarity (M) is 1.5 mol/L.
2. Recall the definition of molarity: \(\text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}}\).
3. Rearrange the molarity formula to solve for moles of solute: \(\text{moles of solute} = \text{Molarity} \times \text{Volume}\).
4. Substitute the known values into the equation: \(\text{moles of NaCl} = 1.5\ \text{mol/L} \times 0.500\ \text{L}\).
5. Multiply the values to find the number of moles of NaCl present in the solution.