What volume of 9.00 M nitric acid is required to prepare 6.50 L of a 1.25 M nitric acid solution?

• A. 7.20 L
• B. 0.903 L
• C. 0.139 L
• D. 1.80 L

Answer: (B)

Verified step by step guidance

1. Identify the known values: the concentration of the stock solution (M₁ = 9.00 M), the volume of the diluted solution (V₂ = 6.50 L), and the concentration of the diluted solution (M₂ = 1.25 M).
2. Recall the dilution equation which relates the concentrations and volumes before and after dilution: \(M_1 \times V_1 = M_2 \times V_2\), where \(V_1\) is the volume of the stock solution needed.
3. Rearrange the dilution equation to solve for \(V_1\): \(V_1 = \frac{M_2 \times V_2}{M_1}\).
4. Substitute the known values into the equation: \(V_1 = \frac{1.25 \times 6.50}{9.00}\).
5. Calculate \(V_1\) to find the volume of 9.00 M nitric acid required to prepare 6.50 L of 1.25 M solution.