How many milliliters of 0.075 M NaCl solution can be prepared by diluting 450 mL of 9.0 M NaCl?

• A. 5,400 mL
• B. 54,000 mL
• C. 4,500 mL
• D. 540 mL

Answer: (B)

Verified step by step guidance

1. Identify the known values: the initial concentration \(C_1 = 9.0\, M\), the initial volume \(V_1 = 450\, mL\), and the final concentration \(C_2 = 0.075\, M\). The final volume \(V_2\) is what we need to find.
2. Recall the dilution equation, which relates the concentrations and volumes before and after dilution: \[C_1 \times V_1 = C_2 \times V_2\]
3. Rearrange the dilution equation to solve for the final volume \(V_2\): \[V_2 = \frac{C_1 \times V_1}{C_2}\]
4. Substitute the known values into the equation: \[V_2 = \frac{9.0\, M \times 450\, mL}{0.075\, M}\]
5. Calculate the value of \(V_2\) to find the volume of the diluted solution in milliliters.