In a combustion analysis lab using pipette rockets, what is the optimal ratio of hydrogen to oxygen gases (by volume) for complete combustion and maximum thrust?

• A. 3:1 hydrogen to oxygen
• B. 1:2 hydrogen to oxygen
• C. 2:1 hydrogen to oxygen
• D. 1:1 hydrogen to oxygen

Answer: (C)

Verified step by step guidance

1. Recall the balanced chemical equation for the combustion of hydrogen gas: \$2H_2 + O_2 \rightarrow 2H_2O$. This equation shows the stoichiometric ratio of hydrogen to oxygen molecules needed for complete combustion.
2. From the balanced equation, note that 2 moles (or volumes) of hydrogen gas react with 1 mole (or volume) of oxygen gas to produce water. This means the ideal volume ratio of hydrogen to oxygen is 2:1.
3. Understand that using this 2:1 ratio ensures all hydrogen and oxygen gases are completely consumed without excess of either gas, which is important for efficient combustion and maximum thrust in pipette rockets.
4. Compare the given options to the stoichiometric ratio: 3:1, 1:2, 2:1, and 1:1. Only the 2:1 ratio matches the balanced chemical equation for complete combustion.
5. Conclude that the optimal hydrogen to oxygen volume ratio for complete combustion and maximum thrust in pipette rockets is 2:1, based on the stoichiometry of the reaction.