How many atoms of nitrogen are present in 10 g of NH_4NO_3?

• A. 1.51 × 10^{22} atoms
• B. 3.02 × 10^{23} atoms
• C. 1.51 × 10^{24} atoms
• D. 1.51 × 10^{23} atoms

Answer: (C)

Verified step by step guidance

1. Determine the molar mass of ammonium nitrate (NH_4NO_3) by adding the atomic masses of all atoms in the formula: 2 nitrogen (N), 4 hydrogen (H), and 3 oxygen (O) atoms. Use the atomic masses: N = 14.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol.
2. Calculate the number of moles of NH_4NO_3 in 10 g by using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\).
3. Since each molecule of NH_4NO_3 contains 2 nitrogen atoms, multiply the number of moles of NH_4NO_3 by 2 to find the moles of nitrogen atoms.
4. Use Avogadro's number, \$6.022 \times 10^{23}$ atoms/mol, to convert moles of nitrogen atoms to the actual number of nitrogen atoms by multiplying the moles of nitrogen by Avogadro's number.
5. The result from the previous step gives the total number of nitrogen atoms in 10 g of NH_4NO_3.