How many moles of HCl are present in 75.0 mL of 0.150 M HCl solution?

• A. 0.0113 mol
• B. 0.1125 mol
• C. 0.0056 mol
• D. 0.0750 mol

Answer: (A)

Verified step by step guidance

1. Identify the given information: volume of the HCl solution is 75.0 mL and the molarity (M) is 0.150 M. Molarity is defined as moles of solute per liter of solution.
2. Convert the volume from milliliters to liters because molarity uses liters: use the conversion \$1\, \text{L} = 1000\, \text{mL}\(, so \)V = \frac{75.0}{1000} = 0.0750\, \text{L}$.
3. Use the molarity formula to find moles of HCl: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\) which rearranges to \(\text{moles of solute} = M \times V\).
4. Substitute the known values into the equation: \(\text{moles of HCl} = 0.150\, \text{mol/L} \times 0.0750\, \text{L}\).
5. Calculate the product to find the number of moles of HCl in the solution.