What is the molarity of an HCl solution prepared by dissolving 52.9 g of HCl in enough water to make 250 mL of solution?

• A. 1.50 M
• B. 2.10 M
• C. 5.80 M
• D. 3.50 M

Answer: (C)

Verified step by step guidance

1. Identify the given information: mass of HCl = 52.9 g, volume of solution = 250 mL.
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter: \(\text{Volume (L)} = \frac{250}{1000}\).
3. Calculate the number of moles of HCl using its molar mass. The molar mass of HCl is approximately 36.46 g/mol, so use the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{52.9}{36.46}\).
4. Use the molarity formula to find the concentration: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\).
5. Substitute the values for moles and volume in liters into the molarity formula to calculate the molarity of the HCl solution.