How many moles of NaNO3 are present in a 44.0 g sample?

• A. 0.52 mol
• B. 0.52 mol
• C. 0.52 mol
• D. 0.52 mol

Answer: (A)

Verified step by step guidance

1. Identify the molar mass of sodium nitrate (NaNO3) by summing the atomic masses of its constituent elements: sodium (Na), nitrogen (N), and oxygen (O). Use the periodic table values for each element's atomic mass.
2. Calculate the molar mass using the formula: \(\text{Molar mass of NaNO}_3 = M_{\text{Na}} + M_{\text{N}} + 3 \times M_{\text{O}}\).
3. Use the given mass of the sample (44.0 g) and the molar mass to find the number of moles with the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\).
4. Substitute the values into the formula: \(\text{moles of NaNO}_3 = \frac{44.0\, \text{g}}{\text{molar mass of NaNO}_3}\).
5. Perform the division to find the number of moles of NaNO3 in the sample.