How many sulfur atoms are present in 5.325 × 10^{-23} grams of sulfur (atomic mass of S = 32.07 g/mol)?

• A. 6.022 × 10^{23} atoms
• B. 10 atoms
• C. 100 atoms
• D. 1 atom

Answer: (D)

Verified step by step guidance

1. Identify the given information: mass of sulfur sample = \$5.325 \times 10^{-23}\( grams, atomic mass of sulfur (S) = 32.07 g/mol, and Avogadro's number = \)6.022 \times 10^{23}$ atoms/mol.
2. Calculate the number of moles of sulfur in the given mass using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{5.325 \times 10^{-23} \text{ g}}{32.07 \text{ g/mol}}\).
3. Use Avogadro's number to convert moles of sulfur to number of atoms: \(\text{number of atoms} = \text{moles} \times 6.022 \times 10^{23} \text{ atoms/mol}\).
4. Substitute the moles calculated in step 2 into the equation in step 3 to find the number of sulfur atoms in the sample.
5. Interpret the result to determine how many sulfur atoms are present, and compare it to the given answer choices.