How many atoms of Cl are present in 6.1 mol of CCl_4?

• A. 6.1 × 10^{24} atoms
• B. 1.5 × 10^{25} atoms
• C. 1.5 × 10^{25} atoms
• D. 1.5 × 10^{25} atoms

Answer: (B)

Verified step by step guidance

1. Identify the number of chlorine (Cl) atoms in one molecule of carbon tetrachloride (CCl_4). Since the formula is CCl_4, there are 4 chlorine atoms per molecule.
2. Recall that 1 mole of any substance contains Avogadro's number of molecules, which is approximately \$6.022 \times 10^{23}$ molecules/mol.
3. Calculate the total number of chlorine atoms in 6.1 moles of CCl_4 by multiplying the number of moles by Avogadro's number and then by the number of Cl atoms per molecule: \(\text{Total Cl atoms} = 6.1 \text{ mol} \times 6.022 \times 10^{23} \frac{\text{molecules}}{\text{mol}} \times 4 \frac{\text{Cl atoms}}{\text{molecule}}\).
4. Set up the multiplication carefully, keeping track of the powers of ten and the coefficients separately to avoid errors.
5. Express the final answer in scientific notation to clearly represent the large number of atoms.