According to the ideal gas law, what volume would be occupied by 2.00 moles of propane gas (C_3H_8) at standard temperature and pressure (STP)?

• A. 2.00 L
• B. 44.8 L
• C. 22.4 L
• D. 11.2 L

Answer: (B)

Verified step by step guidance

1. Identify the known variables: number of moles \(n = 2.00\) moles, temperature \(T = 273.15\ \text{K}\) (standard temperature), and pressure \(P = 1.00\ \text{atm}\) (standard pressure).
2. Recall the ideal gas law equation: \(P \times V = n \times R \times T\), where \(V\) is the volume, \(R\) is the ideal gas constant, \(P\) is pressure, \(n\) is moles, and \(T\) is temperature.
3. Use the ideal gas constant \(R = 0.0821\ \text{L} \cdot \text{atm} / \text{mol} \cdot \text{K}\), which is appropriate for these units.
4. Rearrange the ideal gas law to solve for volume \(V\): \(V = \frac{n \times R \times T}{P}\)
5. Substitute the known values into the equation: \(V = \frac{2.00 \times 0.0821 \times 273.15}{1.00}\), then calculate to find the volume occupied by the propane gas at STP.