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Multiple Choice
Which nuclide is produced when uranium-238 undergoes alpha decay?
A
uranium-234
B
thorium-234
C
plutonium-238
D
protactinium-234
Verified step by step guidance
1
Recall that alpha decay involves the emission of an alpha particle, which is a helium nucleus consisting of 2 protons and 2 neutrons. This means the original nucleus loses 2 protons and 2 neutrons.
Write down the original nuclide: uranium-238, which has an atomic number of 92 (number of protons) and a mass number of 238 (total number of protons and neutrons).
Subtract 2 from the atomic number to account for the loss of 2 protons: 92 - 2 = 90. This new atomic number corresponds to the element thorium.
Subtract 4 from the mass number to account for the loss of 2 protons and 2 neutrons: 238 - 4 = 234. This gives the mass number of the new nuclide.
Combine the new atomic number and mass number to identify the nuclide produced: thorium-234.