How many grams of NaCl are present in 100.0 mL of a 2.50 M NaCl solution?

• A. 2.50 g
• B. 5.85 g
• C. 25.0 g
• D. 14.6 g

Answer: (D)

Verified step by step guidance

1. Identify the given information: the molarity (M) of the NaCl solution is 2.50 M, and the volume (V) of the solution is 100.0 mL.
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: \$1\, \text{L} = 1000\, \text{mL}\(, so \)V = \frac{100.0}{1000} = 0.1000\, \text{L}$.
3. Calculate the number of moles of NaCl using the molarity formula: \(\text{moles} = M \times V = 2.50\, \text{mol/L} \times 0.1000\, \text{L}\).
4. Find the molar mass of NaCl by adding the atomic masses of sodium (Na) and chlorine (Cl): \(\text{Molar mass of NaCl} = 22.99\, \text{g/mol} + 35.45\, \text{g/mol}\).
5. Calculate the mass of NaCl by multiplying the moles by the molar mass: \(\text{mass} = \text{moles} \times \text{molar mass}\).