What is the molarity of a solution prepared by dissolving 63 grams of NaCl in enough water to make 650 mL of solution? (Molar mass of NaCl = 58.44 g/mol)

• A. 0.98 M
• B. 0.15 M
• C. 2.50 M
• D. 1.67 M

Answer: (D)

Verified step by step guidance

1. Identify the given information: mass of NaCl = 63 g, volume of solution = 650 mL, and molar mass of NaCl = 58.44 g/mol.
2. Convert the volume of the solution from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: \(\text{Volume (L)} = \frac{\text{Volume (mL)}}{1000}\).
3. Calculate the number of moles of NaCl using the formula: \(\text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}\).
4. Use the molarity formula to find the molarity of the solution: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\).
5. Substitute the values obtained in the previous steps into the molarity formula to express the molarity of the NaCl solution.