If 50.75 g of a gas occupies 10.0 L at STP, how many liters will 129.3 g of the same gas occupy at STP?

• A. 25.5 L
• B. 12.5 L
• C. 15.0 L
• D. 20.0 L

Answer: (A)

Verified step by step guidance

1. Identify that the problem involves the relationship between mass and volume of a gas at STP (Standard Temperature and Pressure), where the volume of a gas is directly proportional to the number of moles (or mass, given constant molar mass).
2. Calculate the volume occupied per gram of the gas using the given data: volume per gram = \( \frac{10.0\ \text{L}}{50.75\ \text{g}} \).
3. Use this volume per gram to find the volume occupied by 129.3 g of the gas by multiplying: \( \text{Volume} = \left( \frac{10.0}{50.75} \right) \times 129.3 \ \text{L} \).
4. Since the conditions are at STP, no further adjustments for pressure or temperature are needed because volume ratios are directly proportional to moles (or mass for the same gas).
5. Express the final volume in liters, which will be the volume occupied by 129.3 g of the gas at STP.