Given 10.0 grams of C6H12O6 (glucose), how many oxygen atoms are present in the sample?

• A. 2.00 × 10^{24} atoms
• B. 1.20 × 10^{23} atoms
• C. 2.00 × 10^{22} atoms
• D. 2.00 × 10^{23} atoms

Answer: (A)

Verified step by step guidance

1. Calculate the molar mass of glucose (C6H12O6) by summing the atomic masses of all atoms: 6 carbons, 12 hydrogens, and 6 oxygens. Use the atomic masses approximately as C = 12.0 g/mol, H = 1.0 g/mol, and O = 16.0 g/mol. The molar mass formula is \(M = 6 \times 12.0 + 12 \times 1.0 + 6 \times 16.0\) g/mol.
2. Determine the number of moles of glucose in the 10.0 g sample by dividing the mass of the sample by the molar mass: \(n = \frac{10.0 \text{ g}}{M \text{ g/mol}}\).
3. Calculate the total number of glucose molecules by multiplying the number of moles by Avogadro's number (\(N_A = 6.022 \times 10^{23}\) molecules/mol): \(N_{molecules} = n \times N_A\).
4. Find the total number of oxygen atoms by multiplying the number of glucose molecules by the number of oxygen atoms per molecule (6 atoms per glucose molecule): \(N_{O} = N_{molecules} \times 6\).
5. Express the final answer in scientific notation to match the format of the given options.