A mixture of N21g2 and H21g2 reacts in a closed container
to form...

Question

A mixture of N21g2 and H21g2 reacts in a closed container
to form ammonia, NH31g2. The reaction ceases before
either reactant has been totally consumed. At this stage
3.0 mol N2, 3.0 mol H2, and 3.0 mol NH3 are present. How
many moles of N2 and H2 were present originally?

Accepted Answer

Hey everyone. So here we have the reaction between zinc and iodine and it produces zinc iodide. For a mixture of zinc and iron dean we have 1.2 moles of zinc, 2.4 mi of iodine In 2.4 malls of Zinc Iodide were measured before the reactors were used up. Or ask calculate the initial amount of the reactant. They're gonna have zinc plus iodine which is I. Two. It's going to give us zinc iodide which is the N. I. Two. And since this is a synthesis reaction we're gonna have 2.4 moles divided by two. We're gonna split it evenly among the reactant And this gives us 1.2 malls. So now we need to add 1.2 moles the moles of each reactant to calculate the initial amount of the reactant. For zinc we have 1.2 moles That's 1.2 miles. And this will give us 2.4 malls of zinc And for i. d. have 3.4 moles. That's 1.2 miles. And this will give us 4.6 malls of iodine. Thanks for watching my video and I hope it was helpful

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