How many grams of CO_2 are present in 2.80 × 10^{24} molecules of CO_2?

• A. 206 g
• B. 11.2 g
• C. 132 g
• D. 44 g

Answer: (A)

Verified step by step guidance

1. Identify the given quantity: 2.80 \times 10^{24} molecules of CO_2.
2. Recall Avogadro's number, which is 6.022 \times 10^{23} molecules per mole. This allows us to convert molecules to moles using the formula: \\n\\[ \text{moles of CO}_2 = \frac{\text{number of molecules}}{6.022 \times 10^{23}} \\]
3. Calculate the number of moles of CO_2 by dividing 2.80 \times 10^{24} molecules by Avogadro's number.
4. Determine the molar mass of CO_2 by adding the atomic masses: Carbon (C) = 12.01 g/mol and Oxygen (O) = 16.00 g/mol. Since there are two oxygen atoms, molar mass = 12.01 + 2 \times 16.00 g/mol.
5. Calculate the mass of CO_2 by multiplying the number of moles by the molar mass using the formula: \\n\\[ \text{mass of CO}_2 = \text{moles of CO}_2 \times \text{molar mass of CO}_2 \\]