Write the condensed electron configuration for the nickel (III...

Question

Write the condensed electron configuration for the nickel (III) ion and state if it is paramagnetic or diamagnetic.

Accepted Answer

here. It says to write the condense electron configuration of the nickel three ion and state if it is para magnetic or diabetic. So Nickel three Ion means and I three plus three plus means that I have lost three electrons. But what we're gonna do initially is we're gonna figure out the electron configuration off the neutral nickel. Adam Nickel has an atomic number off 28 which means it has 28 electrons. It's electron configuration. Would be are gone four s to three. D eight. Now, if we want to do it for the nickel three plus ion, we need to remove three electrons. Our noble gas portion. We don't look at it because that's kind of locked away in a vault within the brackets here, because the number is four. This is n equals four, because the number here is three. This is an equals three. Remember, we remove our first electrons from the highest shell number, so we're gonna move our first electrons from the four s orbital. We need to lose three electrons total. So both of these electrons here gonna be gone. So for us is completely gone now, so we're gonna have are gone. We need to lose one more electron. It's gonna have to come out of the three deep. We're moving. One electron leaves us with three. D seven. So now if we look, we have are gone. Come, remember, our D sub level has five orbital's within it. Following Hunt's role, we have filled them. We have to fill in seven electron. So up, up, up, up, up That's five. Come back around Here the nickel three ion has three uncared electrons. As long as you have at least one impaired electron, you are para magnetic. So here the condense electron configuration of Nickel three ion is this And because it has at least one impaired electron, it is para magnetic.

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