How many atoms of chlorine are present in 1.00 mol of chlorine gas (Cl_2)?

• A. 3.011 × 10^{23} atoms
• B. 6.022 × 10^{23} atoms
• C. 2.000 × 10^{23} atoms
• D. 1.204 × 10^{24} atoms

Answer: (D)

Verified step by step guidance

1. Recognize that chlorine gas (Cl_2) is a diatomic molecule, meaning each molecule contains 2 chlorine atoms.
2. Recall Avogadro's number, which states that 1 mole of any substance contains \$6.022 \times 10^{23}$ entities (in this case, molecules).
3. Calculate the total number of chlorine atoms by multiplying the number of molecules by 2, since each molecule has 2 atoms: \(\text{Number of atoms} = 2 \times 6.022 \times 10^{23}\).
4. Set up the multiplication to find the total atoms: \$2 \times 6.022 \times 10^{23} = 1.2044 \times 10^{24}$ atoms.
5. Interpret the result as the total number of chlorine atoms present in 1.00 mole of Cl_2 gas.