The chloride of an unknown metal is believed to have the formula
...

Question

The chloride of an unknown metal is believed to have the formula
MCl3. A 2.395-g sample of the compound contains
3.606 * 10 - 2 mol Cl. Find the atomic mass of M.

Accepted Answer

Hi everyone for this problem we're told that an unknown metal forms a compound with roaming and has the formula Nbr five. What is the atomic mass of the metal? If a 6.897 g sample of NBR five contains .0541 moles of browning. So this should be molar mass. And what this question is basically asking us is what is the molar mass of our metal? And moller mass is in grams per mole. And we know the grams Of RNBR five. But what's the moles? That's what we're missing. So let's start off there. We can use what we know about our moles of bro. Mean to figure out what is our mole of the entire sample. So let's write that out. So we're told in the problem that we have 0. 541 moles of roaming. And we want to know how many moles of the sample do we have and we can do this using a multiple ratio. And so and one more of M B R five. How many moles of roaming do we have? We have five malls of roaming and here we can see our molds of grooming cancel. And this is going to give us our moles of the entire sample. So once we calculate that We have 0. moles of our sample. So now that we know our molds of the sample, we can figure out our molar mass of the sample because remember molar masses in grams per mole. We know we have 6.897 g of our sample. And now we just calculated the moles. So let's calculate our molar mass. So our molar mass of M. b. R. five is equal to 6. grams over 0. moles. So we have 637.4 three grams per mole of our sample. M. B. R five. And the question is asking us for the molar mass of the metal. So we know our molar mass of the metal. And we can subtract our mass of grooming from the molar mass of our sample to figure out the mass of the metal. So let's figure out what is our weight of grooming first. So we have five bro means. And each one weighs 904g based off of its atomic weight and the periodic table. So this gives us a weight of 399.52 grams of browning. So we know how many grams we have of our sample. We know how many grams of grooming we have. Let's subtract these two numbers. And when we do, we'll be left with our mass of the metal. So our entire sample is 637. grams of M. B. R five minus R 399.52 g of bro mean Leaves us with 237. grams. and this will be Permal. This is our molar mass of our metal. Okay, and that is the final answer for this problem. This is the molar mass of the metal. I hope this was helpful.

Watch next