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Multiple Choice
For the reaction: sucrose + H2O → glucose + fructose, the experimentally determined rate law is rate = k[sucrose][H2O]^0. What is the order of sucrose in the rate law for this reaction?
A
0
B
2
C
1
D
It cannot be determined from the given information.
Verified step by step guidance
1
Identify the given rate law: rate = k[sucrose][H2O]^0.
Recall that the order of a reactant in a rate law is the exponent to which its concentration is raised.
In the rate law, the exponent of [sucrose] is 1 (since it is written as [sucrose] without an explicit exponent, it implies an exponent of 1).
The exponent of [H2O] is 0, meaning the rate does not depend on the concentration of water.
Therefore, the order of sucrose in the rate law is 1.