For the reaction: sucrose + H2O → glucose + fructose, the experimentally determined rate law is rate = k[sucrose][H2O]^0. What is the order of sucrose in the rate law for this reaction?

• A. 0
• B. 2
• C. 1
• D. It cannot be determined from the given information.

Answer: (C)

Verified step by step guidance

1. Identify the given rate law: rate = k[sucrose][H2O]^0.
2. Recall that the order of a reactant in a rate law is the exponent to which its concentration is raised.
3. In the rate law, the exponent of [sucrose] is 1 (since it is written as [sucrose] without an explicit exponent, it implies an exponent of 1).
4. The exponent of [H2O] is 0, meaning the rate does not depend on the concentration of water.
5. Therefore, the order of sucrose in the rate law is 1.