Balance the following redox reaction in a basic solution

Question

H₂O₂ (aq) + ClO₂(aq) → ClO₂^-(aq) + O₂ (g)

Accepted Answer

in this practice question. We're told to balance the follow Redox reaction in a basic solution. All right, so following step one, we know we look for elements that are not oxygen or hydrogen first. So here we have chlorine with chlorine, so that's going to give us one half reaction, which is Cielo, too, gives me Cielo tube minus. Now all we have left is this compound in this compound. So by default that's going to represent our other half reaction. So we have hte 202 gives us 02 now that we have that. Next, we balance elements that are not oxygen or hydrogen First. Here we have one chlorine and one chlorine, so that's already balanced. Okay, now balance the number of oxygen's by adding water. We have two oxygen on this side to oxygen's on this side, so it's already balanced. Let's go to the other socket. We have to. Oxygen's here and to oxygen's here. Still balance, too. All right, so move on to hydrogen. We balance hydrogen is by adding H plus in the first half reaction. Neither side has hydrogen. On the other half reaction, we have two. Hydrogen is here but not on this side. So put to H plus now the hard part. Figuring out overall charge for each side of the two half reactions Cielo to here has no charge. So it's overall charge on this side of zero. Here we have one negative one charge. So the of all charges minus one remember, add electrons to the more positive side so that it has the same overall charge as this side. So how do we go from zero to minus one? How many electrons do we need to add? We need to add one electron. Let's go to the other side H 202 which is hydrogen peroxide has no charge. So it's zero for the overall side, then here it's two times plus one. So that's plus two again. Add electrons with a more positive side. So that equals this side. How do we go from Ah Plus to charge to a zero charge? We add two electrons. Notice your electrons do not match When they don't match, we have to get to the lowest common multiple. So we have to multiply this equation by two. Everything within it gets multiplied by two. So two Cielo two plus two electrons gives me to see L O to minus. Then we're going to stay here for our other half reaction. We have h 202 gives us 02 plus two h plus plus two electrons Now can slot reaction intermediates. The electrons, remember, are always your reaction intermediates. They always supposed to totally cancel out. Now bring down everything because those are Onley reaction intermediates in this question. So we have to Cielo too. Plus h +202 gives me to say hello to minus plus o two plus two h positive. At this point, we've done all the steps necessary balancing in acidic solution. But again, we're balancing it in basic solution. So we add additional steps. Seven We add O H minus two, both sides based on the amount of H plus remaining. And remember, when you have HPE plus an O. H minus together, they could combine to give us water. So bring down everything to say hello to plus H +202 plus two o h minus gives us to see L O to minus plus o two plus two h +20 So here h 20 is only found on one side, so we don't have to cancel out those H 20 molecules on the product side at all. So this would be our final balance equation in a basic solution.

Balance the following redox reaction in a basic solutionH2O2 (aq) + ClO2 (aq) → ClO2- (aq) + O2 (g)

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Balance the following redox reaction in a basic solution
H₂O₂ (aq) + ClO₂(aq) → ClO₂^-(aq) + O₂ (g)