Which of the following solutions contains the most solute?

• A. 100 mL of 2 M NaCl
• B. 200 mL of 0.5 M NaCl
• C. 50 mL of 3 M NaCl
• D. 150 mL of 1 M NaCl

Answer: (A)

Verified step by step guidance

1. Recall that the amount of solute in a solution can be found using the formula for moles of solute: \(\text{moles of solute} = M \times V\), where \(M\) is the molarity (mol/L) and \(V\) is the volume in liters.
2. Convert all given volumes from milliliters (mL) to liters (L) by dividing by 1000, since molarity is expressed in moles per liter.
3. Calculate the moles of NaCl in each solution by multiplying the molarity by the volume in liters for each case:
4. \[\text{moles} = M \times \left( \frac{\text{volume in mL}}{1000} \right)\]
5. Compare the calculated moles of NaCl for all four solutions to determine which one contains the greatest amount of solute.