How many moles of Cu(NO3)2 are present in 2.35 L of a 2.0 M solution?

• A. 1.18 mol
• B. 0.85 mol
• C. 4.70 mol
• D. 2.35 mol

Answer: (C)

Verified step by step guidance

1. Identify the given information: volume of the solution (V) = 2.35 L and molarity (M) = 2.0 M. Molarity is defined as moles of solute per liter of solution.
2. Recall the formula relating moles, molarity, and volume: \(\text{Molarity} (M) = \frac{\text{moles of solute} (n)}{\text{volume of solution} (V)}\).
3. Rearrange the formula to solve for moles of solute: \(n = M \times V\).
4. Substitute the known values into the equation: \(n = 2.0\, \text{mol/L} \times 2.35\, \text{L}\).
5. Calculate the product to find the number of moles of Cu(NO\_3)\_2 in the solution.