What volume of 0.550 M KBr solution can be prepared by diluting 100.0 mL of 2.50 M KBr?

• A. 455 mL
• B. 500 mL
• C. 350 mL
• D. 220 mL

Answer: (A)

Verified step by step guidance

1. Identify the known values: the initial concentration \(C_1 = 2.50\, M\), the initial volume \(V_1 = 100.0\, mL\), and the final concentration \(C_2 = 0.550\, M\). The final volume \(V_2\) is what we need to find.
2. Recall the dilution equation which relates concentrations and volumes before and after dilution: \[C_1 \times V_1 = C_2 \times V_2\]
3. Rearrange the equation to solve for the final volume \(V_2\): \[V_2 = \frac{C_1 \times V_1}{C_2}\]
4. Substitute the known values into the equation: \[V_2 = \frac{2.50\, M \times 100.0\, mL}{0.550\, M}\]
5. Calculate the value of \(V_2\) to find the volume of the 0.550 M KBr solution after dilution.