Approximately how many grams of Fe2O3 are present in 0.82 mol Fe2O3?

• A. 159 g
• B. 131 g
• C. 0.82 g
• D. 52 g

Answer: (B)

Verified step by step guidance

1. Identify the given quantity and what is asked: You have 0.82 moles of Fe\_2O\_3 and need to find the mass in grams.
2. Calculate the molar mass of Fe\_2O\_3 by adding the atomic masses of its elements: Fe (iron) has an atomic mass of approximately 55.85 g/mol, and O (oxygen) has an atomic mass of approximately 16.00 g/mol. Since Fe\_2O\_3 contains 2 Fe atoms and 3 O atoms, the molar mass is calculated as \$2 \times 55.85 + 3 \times 16.00$ g/mol.
3. Use the formula relating moles, molar mass, and mass: \(\text{mass} = \text{moles} \times \text{molar mass}\).
4. Substitute the given moles (0.82 mol) and the calculated molar mass of Fe\_2O\_3 into the formula to find the mass in grams.
5. Perform the multiplication to find the mass of Fe\_2O\_3 corresponding to 0.82 moles.