How many atoms of H are present in 2.8 mol of N2H4?

• A. 4.8 × 10^{24} atoms
• B. 6.7 × 10^{24} atoms
• C. 1.1 × 10^{24} atoms
• D. 2.8 × 10^{23} atoms

Answer: (B)

Verified step by step guidance

1. Identify the chemical formula of the compound given, which is N\_2H\_4. This means each molecule contains 2 nitrogen atoms and 4 hydrogen atoms.
2. Determine the number of moles of hydrogen atoms in 2.8 moles of N\_2H\_4 by multiplying the moles of N\_2H\_4 by the number of hydrogen atoms per molecule: \$2.8 \text{ mol} \times 4 = 11.2 \text{ mol H atoms}$.
3. Recall that 1 mole of any substance contains Avogadro's number of particles, which is approximately \$6.022 \times 10^{23}$ particles/mol.
4. Calculate the total number of hydrogen atoms by multiplying the moles of hydrogen atoms by Avogadro's number: \$11.2 \text{ mol} \times 6.022 \times 10^{23} \text{ atoms/mol}$.
5. Express the final answer in scientific notation to match the format of the options provided.