How many moles of Na2CO3 are present in 0.40 L of a 3.5 M Na2CO3 solution?

• A. 0.40 mol
• B. 1.4 mol
• C. 8.75 mol
• D. 0.14 mol

Answer: (B)

Verified step by step guidance

1. Identify the given information: the volume of the solution is 0.40 L and the molarity (M) of the Na2CO3 solution is 3.5 M. Molarity is defined as moles of solute per liter of solution.
2. Recall the formula for molarity: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\).
3. Rearrange the formula to solve for moles of solute: \(\text{moles of solute} = M \times \text{liters of solution}\).
4. Substitute the known values into the equation: \(\text{moles of Na}_2\text{CO}_3 = 3.5\, M \times 0.40\, L\).
5. Calculate the product to find the number of moles of Na2CO3 present in the solution.