Calculate the volume (mL) of acetone, C₃ H₆ O, (density = 0.786 g/mL) that can be vaporized at its normal boiling point with 345 kJ of heat. ΔH_vap for acetone is 29.1 kJ/mol.

• A. 15.1 mL
• B. 151 mL
• C. 541 mL
• D. 688 mL
• E. 876 mL

Answer: (E)

Verified step by step guidance

1. Identify the given values: the heat provided (345 kJ), the density of acetone (0.786 g/mL), and the enthalpy of vaporization (ΔHvap = 29.1 kJ/mol).
2. Calculate the number of moles of acetone that can be vaporized using the formula: \( \text{moles} = \frac{\text{heat}}{\Delta H_{\text{vap}}} \). Substitute the given values to find the moles.
3. Convert the moles of acetone to grams using the molar mass of acetone (C3H6O). The molar mass is calculated as: \( 3(12.01) + 6(1.01) + 16.00 \) g/mol.
4. Use the density of acetone to convert the mass (in grams) to volume (in mL) using the formula: \( \text{volume} = \frac{\text{mass}}{\text{density}} \).
5. Substitute the calculated mass and the given density into the formula to find the volume of acetone that can be vaporized.