To calculate the volume of a simple cubic unit cell composed of atoms with a radius of 2.5 angstroms, we start by recalling that the volume of a cube is given by the formula:
V = a³
where V is the volume and a is the edge length of the cube. For a simple cubic unit cell, the edge length a is twice the radius of the atom:
a = 2r
Given that the radius r is 2.5 angstroms, we first convert this radius into centimeters. The conversion factor is:
1 \(\text{ angstrom}\) = 10^{-10} \(\text{ meters}\) = 10^{-8} \(\text{ centimeters}\)
Thus, the radius in centimeters is:
r = 2.5 \(\times\) 10^{-8} \(\text{ cm}\)
Now, we can calculate the edge length:
a = 2 \(\times\) r = 2 \(\times\) (2.5 \(\times\) 10^{-8}) = 5.0 \(\times\) 10^{-8} \(\text{ cm}\)
Next, we cube the edge length to find the volume:
V = (5.0 \(\times\) 10^{-8})^3 = 1.25 \(\times\) 10^{-23} \(\text{ cm}\)^3
Therefore, the volume of the simple cubic unit cell is:
V \(\approx\) 1.3 \(\times\) 10^{-22} \(\text{ cm}\)^3

