What volume (in liters) of a 6.67 M NaCl solution contains 3.12 mol NaCl?

• A. 21.0 L
• B. 0.0214 L
• C. 2.14 L
• D. 0.468 L

Answer: (D)

Verified step by step guidance

1. Identify the known quantities: the molarity (M) of the NaCl solution is 6.67 M, and the amount of NaCl in moles is 3.12 mol.
2. Recall the definition of molarity: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\).
3. Rearrange the molarity formula to solve for volume: \(V = \frac{\text{moles of solute}}{M}\).
4. Substitute the known values into the equation: \(V = \frac{3.12\ \text{mol}}{6.67\ \text{mol/L}}\).
5. Calculate the volume in liters by performing the division to find the volume of solution that contains 3.12 mol of NaCl.