A 20.0 mL sample of 0.10 M HCl(aq) is taken. How many moles of HCl are present in the sample?

• A. 0.020 mol
• B. 0.10 mol
• C. 0.0020 mol
• D. 0.00020 mol

Answer: (C)

Verified step by step guidance

1. Identify the given information: volume of HCl solution is 20.0 mL and its concentration is 0.10 M (moles per liter).
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: \$1\, \text{L} = 1000\, \text{mL}\(. So, \)V = \frac{20.0}{1000} = 0.0200\, \text{L}$.
3. Recall the formula relating moles, molarity, and volume: \(n = M \times V\), where \(n\) is the number of moles, \(M\) is the molarity, and \(V\) is the volume in liters.
4. Substitute the known values into the formula: \(n = 0.10\, \text{mol/L} \times 0.0200\, \text{L}\).
5. Calculate the product to find the number of moles of HCl in the sample.