What is the molarity of a solution prepared by dissolving 24 grams of LiOH in 200 mL of water? (Molar mass of LiOH = 23.95 g/mol)

• A. 0.50 M
• B. 1.20 M
• C. 2.00 M
• D. 5.01 M

Answer: (D)

Verified step by step guidance

1. Identify the formula for molarity, which is the number of moles of solute divided by the volume of solution in liters: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
2. Calculate the number of moles of LiOH by using its mass and molar mass: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{24\ \text{g}}{23.95\ \text{g/mol}}\).
3. Convert the volume of the solution from milliliters to liters because molarity requires liters: \$200\ \text{mL} = 0.200\ \text{L}$.
4. Substitute the moles of LiOH and the volume in liters into the molarity formula: \(M = \frac{\text{moles of LiOH}}{0.200\ \text{L}}\).
5. Perform the division to find the molarity of the solution.