How many atoms of neon are present in 0.378 g of neon (Ne)?

• A. 2.53 × 10^{21} atoms
• B. 6.02 × 10^{23} atoms
• C. 1.12 × 10^{22} atoms
• D. 9.45 × 10^{20} atoms

Answer: (C)

Verified step by step guidance

1. Identify the given information: mass of neon (Ne) is 0.378 g.
2. Find the molar mass of neon (Ne) from the periodic table, which is approximately 20.18 g/mol.
3. Calculate the number of moles of neon using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{0.378\ \text{g}}{20.18\ \text{g/mol}}\).
4. Use Avogadro's number, \$6.022 \times 10^{23}\( atoms/mol, to convert moles of neon to number of atoms: \)\text{atoms} = \text{moles} \times 6.022 \times 10^{23}$.
5. Combine the calculations to find the total number of neon atoms in 0.378 g without performing the final multiplication.