How many moles of CH3OH are present in 50.0 mL of a 0.400 M CH3OH solution?

• A. 0.0400 mol
• B. 0.0080 mol
• C. 0.0200 mol
• D. 0.200 mol

Answer: (C)

Verified step by step guidance

1. Identify the given information: the volume of the solution is 50.0 mL and the molarity (M) of CH3OH is 0.400 M. Remember that molarity is defined as moles of solute per liter of solution.
2. Convert the volume from milliliters to liters because molarity uses liters: use the conversion \$1\, \text{L} = 1000\, \text{mL}\(, so \)V = \frac{50.0}{1000} = 0.0500\, \text{L}$.
3. Use the molarity formula to find moles of CH3OH: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\) which rearranges to \(\text{moles of solute} = M \times V\).
4. Substitute the known values into the equation: \(\text{moles of CH3OH} = 0.400\, \text{mol/L} \times 0.0500\, \text{L}\).
5. Calculate the product to find the number of moles of CH3OH in the solution.