How many sodium atoms are present in 0.2310 g of sodium (Na)?

• A. 9.98 × 10^{23} atoms
• B. 6.04 × 10^{21} atoms
• C. 1.00 × 10^{22} atoms
• D. 2.42 × 10^{20} atoms

Answer: (B)

Verified step by step guidance

1. Identify the given information: mass of sodium (Na) is 0.2310 g.
2. Find the molar mass of sodium (Na) from the periodic table, which is approximately 22.99 g/mol.
3. Calculate the number of moles of sodium using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{0.2310\ \text{g}}{22.99\ \text{g/mol}}\).
4. Use Avogadro's number, \$6.022 \times 10^{23}\( atoms/mol, to convert moles of sodium to number of atoms: \)\text{atoms} = \text{moles} \times 6.022 \times 10^{23}$.
5. Perform the multiplication to find the total number of sodium atoms in 0.2310 g of sodium.