How many sulfur atoms are present in 0.45 mol of BaSO4?

• A. 1.1 × 10^{23} atoms
• B. 6.0 × 10^{23} atoms
• C. 2.7 × 10^{23} atoms
• D. 4.5 × 10^{22} atoms

Answer: (C)

Verified step by step guidance

1. Identify the chemical formula of the compound: BaSO\_4. This tells us that each formula unit contains 1 sulfur (S) atom.
2. Recall that 1 mole of any substance contains Avogadro's number of entities, which is approximately 6.022 \times 10^{23} atoms or molecules.
3. Since each mole of BaSO\_4 contains 1 mole of sulfur atoms, the number of sulfur atoms in 0.45 moles of BaSO\_4 is calculated by multiplying 0.45 moles by Avogadro's number.
4. Write the expression for the number of sulfur atoms: Number of S atoms = 0.45 \times 6.022 \times 10^{23}.
5. Perform the multiplication to find the total number of sulfur atoms present in 0.45 moles of BaSO\_4.