How many grams are present in 0.885 moles of manganese (Mn)? (Atomic mass of Mn = 54.94 g/mol)

• A. 48.6 g
• B. 62.3 g
• C. 54.94 g
• D. 0.885 g

Answer: (A)

Verified step by step guidance

1. Identify the given information: the number of moles of manganese (Mn) is 0.885 moles, and the atomic mass of Mn is 54.94 g/mol.
2. Recall the relationship between moles, molar mass, and mass: \(\text{mass} = \text{moles} \times \text{molar mass}\).
3. Set up the calculation using the formula: \(\text{mass} = 0.885 \text{ moles} \times 54.94 \text{ g/mol}\).
4. Multiply the number of moles by the atomic mass to find the mass in grams.
5. Express the final answer in grams, which represents the mass of 0.885 moles of manganese.