How many atoms of neon are present in 1.30 moles of neon?

• A. 6.02 × 10^{23} atoms
• B. 7.83 × 10^{23} atoms
• C. 1.30 × 10^{24} atoms
• D. 3.90 × 10^{23} atoms

Answer: (B)

Verified step by step guidance

1. Identify the given quantity: 1.30 moles of neon atoms.
2. Recall that 1 mole of any substance contains Avogadro's number of particles, which is \$6.02 \times 10^{23}$ atoms/mole.
3. Set up the calculation to find the total number of neon atoms by multiplying the number of moles by Avogadro's number: \(\text{Number of atoms} = 1.30 \text{ moles} \times 6.02 \times 10^{23} \text{ atoms/mole}\).
4. Perform the multiplication of the numerical coefficients (1.30 and 6.02) and add the exponents of 10 accordingly to express the answer in scientific notation.
5. Express the final answer as the total number of neon atoms present in 1.30 moles, ensuring the units are atoms.